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5n^2-13n-60=0
a = 5; b = -13; c = -60;
Δ = b2-4ac
Δ = -132-4·5·(-60)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-37}{2*5}=\frac{-24}{10} =-2+2/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+37}{2*5}=\frac{50}{10} =5 $
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